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Mathematics 7 Online
OpenStudy (anonymous):

e^3x/x^2+1 limit infinity

OpenStudy (zarkon):

infinity

OpenStudy (zarkon):

use L'Hospitals rule or the taylor expansion of e^(3x) to show this

OpenStudy (anonymous):

So the derivative of top & bottom, and then x = 0, right?

OpenStudy (zarkon):

you will have to use L'Hopitals rule a couple times...each time you try and take the limit as x->infinity

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