Okay here's another but at least I got the GCF out
24r^3 + 166r^2 - 168r
I factored out 4r to get:
4r (6r^2 + 29r - 42)
but of course this is where I get stuck
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OpenStudy (anonymous):
166/4 = 83/2
OpenStudy (anonymous):
I'm sorry wrote it wrong, ahhhhh, it's 116r not 166r
OpenStudy (anonymous):
original problem is 24r^3 + 116r^2 - 168r
OpenStudy (anonymous):
now u factorise the quadratic equation in the bracket...
OpenStudy (anonymous):
does the problem allow you to use the quadratic method of finding r?
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OpenStudy (anonymous):
then i factored out 4r to get 4r(6r^2 + 29r - 42)
OpenStudy (anonymous):
ur factors are correct
now factior the quadratic
myininaya (myininaya):
now looking at 6r^2+29r-42
we need to find two factors of 6(-42) that multiply to be 6(-42) and add up to be 29
6(-42)=36(-7)
36-7=29
so we have 6r^2+36r-7r-42
now factor by grouping
OpenStudy (anonymous):
hint: factors of -42 are +6 and -7
OpenStudy (anonymous):
i got (6r-7)(r+6)
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OpenStudy (anonymous):
right
myininaya (myininaya):
so don't forget the 4r and you are done
OpenStudy (anonymous):
by jove you've got it!
OpenStudy (anonymous):
so it's 4r(6r-7)(r+6)
OpenStudy (anonymous):
yep
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