Question

Determine whether u and v are orthogonal, parallel, or neither.

u = <15,45>
v = <-5,12>

Answer 1

Why was my answer deleted again?

Answer 2

If their dot product is 0, they are orthogonal.
If one is a scalar multiple of the other, they are parallel.
If neither, then neither.

Answer 3

Your answer was deleted because it wasn't helpful

Answer 4

The same reason many of your answers get deleted.

Answer 5

Someone apparently gave it a medal...

Answer 6

Do you imagine that medals have any significance?

Answer 7

U should know by now that I am not motivated by medals...

I was wondering who gave a medal to an unhelpful answer.

Answer 8

I guess we will never know...

Answer 9

If the answer isnt informative, tht dsnt cost a removal! :O

Answer 10

I disagree.

Answer 11

Why?

Answer 12

We've had this conversation before.

Answer 13

@estudier, wht one medal will do?
tht dsnt count.

Answer 14

@polpak, but still.
if u want.. u may elaborate my answer, rather than deleting that!

Answer 15

I would like to see the answer, show me in chat..

Answer 16

If you don't want your answers deleted there is a simple fix.
Don't give answers. Give help.

Answer 17

@estuder My answer will be deleted again!
lol

Answer 18

In chat...

Answer 19

@polpak, there it is writeen, Needs a good answer..
there isnt written, need a good HELP!

Answer 20

The response given was:
\[\huge \text{Neither}\]

Answer 21

I think I left off an exclamation point.

Answer 22

Fair enough, no guarantee it's right, either...

Answer 23

I don't like students coming here to get answers rather than learning. I don't like tutors giving answers and not help. The two feed into each other.

Answer 24

@saifoo, u had to have dotted them to give the answer, why not just post the work?

Answer 25

@estudier:
the answer is correct!

Answer 26

"I don't like students coming here to get answers rather than learning. I don't like tutors giving answers and not help. The two feed into each other."

Quite a few feel like this, me too.

Answer 27

Nobody cares if you can solve it saifoo.

Answer 28

@polpak, is that written in the Terms & Condition?

Answer 29

We're supposed to be helping the students solve things. Not doing it for them.

Answer 30

If you don't like helping students feel free to stop.

Answer 31

Didn't say it wasn't right, I said you must have done the dot product to answer, why not post your work?

Answer 32

If you don't like answers begin deleted, feel free to not post them.

Answer 33

But I'm tired of you being shocked and surprised everytime it happens

Answer 34

We've had this conversation before.

Answer 35

um wow, but i kinda still need help and now i cant see where the helping comment was :(

Answer 36

u • v = <15, 45> • <-5, 12> = (15)(-5) + (45)(12) = -75 + 540 = 465.

Since u • v is non-zero, u and v are not orthogonal.

If u and v are parallel, then there should be some number c such that u = cv. However:

u = cv
<==> <15, 45> = <-5c, 12c>.

Upon comparing the x components, we see that c = -3. However, upon comparing the y components, we see that c = 15/4. Since these values of c are inconsistent, there is no value of c such that u = cv and so u and v are not parallel.

Answer 37

@polpak, i askd u is that written in the Terms & Con?

Answer 38

@jan, my answer was correct/

Answer 39

@estu, here u go with the solution too! ^.^

Answer 40

I would have given u medal myself for that:-)

Answer 41

I feel that such answers are a violation of the anti-cheating policy. And I delete them accordingly.

Answer 42

@estu, medals dnt count that much, i have many.. Lol.

Answer 43

@polpak, then there must be written: "NEEDS A GOOD HELP".
or something like that, lol.

Answer 44

thank you i get it now, wow you've taught me more than my precal teacher has , THE WHOLE YEAR, GRATZI

Answer 45

I would _prefer_ that you work with the student to help them arrive at the correct solution. But at a minimum I require that you at least explain what is being done and why.

Answer 46

@jah, lol.. thnks man! :)

Answer 47

"I would _prefer_ that you work with the student to help them arrive at the correct solution. But at a minimum I require that you at least explain what is being done and why."

I think in general this is the correct approach. I suppose there might be occasional exceptions that prove the rule.

Answer 48

@saifoo

Now u have an admirer...

Answer 49

Better than a medal....

Answer 50

@pol, thts wht u _prefer_ man!

Answer 51

Lol @ estudier! ^.-