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Can anyone give me the correct answer on this problem please? Question attached.
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first work on getting the lcd of the top and bottom part
multiply the outermost fraction by \(\frac{b}{b}\) to clear the complex fraction.
Simba, same method as your last problem!
yes like math cruncher 4 said. that way you combine the top term into one fraction and the bottom term also will become one fraction. Then you can simply multiply the top fraction by the reciprocal of the bottom
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Ok hang on
\[\frac{a+\frac{a}{b}}{b - \frac{81}{b}}\]\[= \frac{a+\frac{a}{b}}{b - \frac{81}{b}}\cdot 1\]\[=\frac{a+\frac{a}{b}}{b - \frac{81}{b}}\cdot \frac{b}{b}\]\[=...\]
a(b+1)/(b-9)(b+9)?
Is that correct because that's what I got.
Yep, seems right to me.
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