Question

Describe the nature of the roots for this equation.
x^2+3x-7=0

A.Two complex roots
B.One real, double root
C.Two real, rational roots
D.Two real, irrational roots

Answer 1

The trick to this is to use the descriminant of the quadratic.

Answer 2

Are you familiar with the term?

Answer 3

determinant*

Answer 4

oops discriminant*

Answer 5

delta = b^2 - 4(a*c)

Answer 6

ya

Answer 7

Ok:

\[b^2 - 4ac > 0 \implies \text{ 2 real roots}\]
\[b^2 - 4ac < 0 \implies \text{ 2 imaginary(complex) roots}\]
\[b^2 - 4ac = 0 \implies \text{ 1 real root}\]

And if \(\sqrt{b^2 - 4ac}\) is irrational , the roots will be irrational.

Answer 8

so d?