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Identify the vertex and the axis of symmetry for the graph y=3(x-3)^2+4
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vertex is (3,4)
this is in the form \[y=a(x-h)^2+k\] which is a parabola with vertex (h,k) so you just read off your answer
Would x=-3 or positive ?
no x = 3
reason as follows. if x = 3 then x-3=3-3 =0 so the square term is 0
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and since the square term is a SQUARE the smallest it can be is zero. so the smallest y can be is 4, and it if 4 if x is 3
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