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Simplify: square root -8 times square root -2
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-4.
\[\sqrt{-8{\sqrt{-2}}}\] this?
but i thought you couldn't square root a negative number? The second one looks better
I got -4. It is i square root 8 minus i square root 2. Which gives you i^2 square root 16. Which is (-1)(4). And gives you the answer -4.
Shouldn't it be \[\sqrt{-8}\sqrt{-2} = \sqrt{16}?\]
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thats what i was thinking at first... i wasnt sure
By the way, you will learn later on that you can take the square of a negative number.
ans \[2^{7/4}\times i ^{3/2}\]
i is imaginari number its value(\[\sqrt{-1}\])
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