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What is the correct solution for the integral int_{?}^{?} sin ^-1*xdx
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is that: \(sin^{-1}(x) dx\) ??
otherwise it makes no sense; \[\int sin^{-1} * x\ dx\text{ ??}\]
yeah its as you put the second one :)
the second one makes no sense. sin-1 is an operator/function name. It has no inherent value unless it is being used on something ... sin-1(4/56) has meansing sin-1(x/2) has meaning sin-1 .... has no meaning since there is nothing for it to act upon
Lol. It was probably put there to trick me. But thanks to you it didnt :)
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but idk. i guess ill just guess
:) math can be just a jibberished as english.
I know right:/ but you have no clue amistre?
as is; its just nonsense. do we have any options for answers?
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