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Mathematics 11 Online
OpenStudy (anonymous):

write an equation for the graphs http://tinypic.com/view.php?pic=ej8ke1&s=7

OpenStudy (anonymous):

the picture you need zoom in I can see better

OpenStudy (anonymous):

click the picture to zoom

OpenStudy (dumbcow):

Horizontal hyperbola. center (0,0) vertices at (+-3,0) asymptote looks like y = +- 2/3x

OpenStudy (anonymous):

so the full equation is y=+-2/3x?

OpenStudy (anonymous):

and which number is that 1

OpenStudy (dumbcow):

oh sorry #1, #2,3 are parabolas no the asymptote is 2/3x not the equation of the hyperbola use the reference sheet i attached on other post

OpenStudy (anonymous):

3) Vertex: (2,3) vertex equation form is : x= (y-3)^2 +2

OpenStudy (anonymous):

thanks nancy

OpenStudy (dumbcow):

2) vertex at (0,0) focus point at (2,0) 1/4a = 2 a=1/8

OpenStudy (dumbcow):

3) it opens in negative direction focus point at (-1,3) 1/4a = -3 a = -1/12

OpenStudy (dumbcow):

general equation of horizontal parabola \[x = a(y-k)^{2} + h\]

OpenStudy (anonymous):

isnt it suppose to be y=?

OpenStudy (anonymous):

ur answers are kinda wierd

OpenStudy (dumbcow):

its y= if the parabola opens up/down its "x=" if it opens right/left haha i know these are weird graphs..but they are correct

OpenStudy (anonymous):

ok thanks

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