Question

Some please tell me what you get for an answer! Solve by the quadratic formula: 4x^2-3x+1=0

Answer 1

if u notice it, the discriminant is less than zero, so it has no real solutions

Answer 2

So what should I put? And what's "discriminant"?

Answer 3

\[x=\frac{-b \pm \sqrt{b^2-4ac}}{2a}, ax^2+bx+c=0\]

Answer 4

meaning the b^2-4ac part is less than zero

Answer 5

I know how to do it myininaya, I just got confusing answers

Answer 6

therefore, you can't take the square root of it

Answer 7

\[a \neq 0\]

Answer 8

what is a
what is b
what is c

Answer 9

So what would I write for an answer? Not possible?

Answer 10

what is a
what is b
what is c

Answer 11

i will help you if you answer my questions

Answer 12

Ok, Ok, a=4 b=-3 c=1

Answer 13

\[\frac{-(-3) \pm \sqrt{(-3)^2-4(4)(1)}}{2(4)}\]

Answer 14

\[\frac{3 \pm \sqrt{9-16}}{8}=\frac{3 \pm \sqrt{-7}}{8}\]

Answer 15

\[=\frac{3 \pm i \sqrt{7}}{8}\]

Answer 16

What does i mean?

Answer 17

imaginary
\[\sqrt{-1}=i\]

Answer 18

not real

Answer 19

So is the third to last thing that you put be the answer on my test Wednesday? Or would it be some other term?