Question

A marksman hits a target with probability 5/6 Assuming independence for successive firings, find the probabilities of getting

(a) One miss followed by two hits.
(b) Two misses and one hit (in any order).

Answer 1

a)\[\frac{1}{6}\cdot\frac{5}{6}\cdot\frac{5}{6}\]

Answer 2

\[_3C_1\left(\frac{5}{6}\right)^1\left(\frac{1}{6}\right)^2\]

Answer 3

for b

Answer 4

so i just multiply 5/6 and (1/6)^2

Answer 5

3*(5/6)*(1/6)^2

Answer 6

A) (1/6)(5/6)(5/6)=25/216

B) (1/6)(1/6)(5/6)=5/216

Answer 7

(b) is 5/72