What is the value of -81^(1/4)
this is really: \[\sqrt[4]{-81}\]
-3
langrangeson, when i put it in my calculator it won't do it J3553, I got that when I put -81^.25 but -3times-3=9 9times-3=-27 -27times-3=81 not -81
That's why I'm so confused
-81^1/4 = (-1)^1/4 x (81)^1/4 now, -1 = i^2 so -81^1/4 = i^1/2 x 3 i^1/2 = 1/sqrt(2) x(1+i)
What just happened??????
Someone please help!
calm down everything will be okay, do you still need help?
Yes! Look at the third post.
okay, this is what we will do, first we factor out the negative in the form of -1
Ok, I just need to get it straight whether it's neg or pos 3, so lets do this
OH! I think I get where you're going with this!
right, so what i meant to type is :\[-1*\sqrt[4]{81}\]
Ok! Thank you so much!
now just do your thing from there
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