Question

How do I simplify this expression? Here is the problem:

http://www.wolframalpha.com/input/?i=1+%2B+%281+%2F+%281+%2B+%281+%2F+%28+1+%2B+x%29%29%29%29

Answer 1

http://www.wolframalpha.com/input/?i=simplify+1+%2B+%281+%2F+%281+%2B+%281+%2F+%28+1+%2B+x%29%29%29%29

Answer 2

that really doesn't explain much...

Answer 3

LOL.

Answer 4

:) Oh well. Let me explain

Answer 5

use the divide sign to bring them aside & then convert them to multiply by Flipping.

Answer 6

lol..

Answer 7

It kinda tells ya 2-1/(x+2)

Answer 8

SJSharks003: well, I'm having trouble getting to the simplified expression

Answer 9

OH.. I get what you're saying.. you want to know how to get there ;D

Answer 10

1+1/(1+x)=(1+x)/(1+x) + 1/(1+x). Add like-denominator fractions you get (x+2)/(x+1)

Answer 11

1/((x+2)/(x+1)) is like taking the reciprocal of (x+2)/(x+1) and so the reciprocal of that is (x+1)/(x+2)

Answer 12

now add 1 and (x+1)/(x+2) we get (2x+3)/(x+2)

Answer 13

anhhuyalex: Thank you so much!

Answer 14

\[ 1+\frac{1}{1+\frac{1}{1+x}} \]


\[ 1+\frac{1}{\frac{1+x}{1+x}+\frac{1}{1+x}} \]


\[ 1+\frac{1}{\frac{1+x+1}{1+x}} \]


\[ 1+\frac{1}{\frac{x+2}{1+x}} \]


\[ 1+\frac{1+x}{x+2} \]


\[ \frac{x+2}{x+2}+\frac{1+x}{x+2} \]


\[ \frac{x+2+(1+x)}{x+2} \]


\[ \frac{2x+3}{x+2} \]

Answer 15

Thank you :)

Answer 16

Hey jim, how did you write the fraction thing in the equations?

Answer 17

type \ followed by a [ then type a bunch of LaTex commands

or...


you can hit the "Equation" button below to enter the fractions

|
V

Answer 18

oh remember to close off the commands by a \ then a ]