(g+1)/(g-5)÷(7g+7)/(g-2)
now you can write the question as (g+1)[{1/g-5}+{7/g-2}] right?
i jus took g+1 common
now cross multiply
you will get (g+1)[{(g-2)+7(g-5)}/(g-2)(g-5)] right?
right
now you will simplify the bracket to get your answer as (g+1)(8g-37)/(g-5)(g-2).. n ur done:)
is that the answer you want?
and that is where I get stuck
what is that you want to do? simplify it more?
yes
i believe it cant be simplified further... No it can't be.. do you have the solution?
no
then this should be the final answer.. Still confirm it.. But i dont think it can go further.. though cwd16 has something to say.
\[\frac{g-2}{7(g-5)}\]
how did you get that hero?
Can you put a bracket for your question please? 'Cause you can get different answers. This is how I understood your question [(g+1)/(g-5)] ÷ [(7g+7)/(g-2)] So if this is what you're really asking, this is my solution. It basically becomes (g+1)/(g-5) * (g-2)/7(g+1) Then you cancel out (g+1) So you now have (g-2)/7(g-5)
Actually multiplying it out by hand
wait a sec.. is it division or addition?????????
OMG!!!!!!!!!!!!!!! i took it as +!!!! Sorry vincent
(g-2)/7(g-5) is the answer
you thought the division sign was a plus sign? Yeah, it happens...I guess
yes hero i did
Join our real-time social learning platform and learn together with your friends!