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OpenStudy (anonymous):

(g+1)/(g-5)÷(7g+7)/(g-2)

OpenStudy (akshay_budhkar):

now you can write the question as (g+1)[{1/g-5}+{7/g-2}] right?

OpenStudy (akshay_budhkar):

i jus took g+1 common

OpenStudy (akshay_budhkar):

now cross multiply

OpenStudy (akshay_budhkar):

you will get (g+1)[{(g-2)+7(g-5)}/(g-2)(g-5)] right?

OpenStudy (anonymous):

right

OpenStudy (akshay_budhkar):

now you will simplify the bracket to get your answer as (g+1)(8g-37)/(g-5)(g-2).. n ur done:)

OpenStudy (akshay_budhkar):

is that the answer you want?

OpenStudy (anonymous):

and that is where I get stuck

OpenStudy (akshay_budhkar):

what is that you want to do? simplify it more?

OpenStudy (anonymous):

yes

OpenStudy (akshay_budhkar):

i believe it cant be simplified further... No it can't be.. do you have the solution?

OpenStudy (anonymous):

no

OpenStudy (akshay_budhkar):

then this should be the final answer.. Still confirm it.. But i dont think it can go further.. though cwd16 has something to say.

hero (hero):

\[\frac{g-2}{7(g-5)}\]

OpenStudy (akshay_budhkar):

how did you get that hero?

OpenStudy (anonymous):

Can you put a bracket for your question please? 'Cause you can get different answers. This is how I understood your question [(g+1)/(g-5)] ÷ [(7g+7)/(g-2)] So if this is what you're really asking, this is my solution. It basically becomes (g+1)/(g-5) * (g-2)/7(g+1) Then you cancel out (g+1) So you now have (g-2)/7(g-5)

hero (hero):

Actually multiplying it out by hand

OpenStudy (akshay_budhkar):

wait a sec.. is it division or addition?????????

OpenStudy (akshay_budhkar):

OMG!!!!!!!!!!!!!!! i took it as +!!!! Sorry vincent

OpenStudy (akshay_budhkar):

(g-2)/7(g-5) is the answer

hero (hero):

you thought the division sign was a plus sign? Yeah, it happens...I guess

OpenStudy (akshay_budhkar):

yes hero i did

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