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OpenStudy (anonymous):
pls. help me solve this.
find the derivatives
y=x/x^2-1
f(x)=x^2+1/x^2-1
pls show your solution.
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OpenStudy (akshay_budhkar):
the working is..
OpenStudy (anonymous):
how is it done?
OpenStudy (akshay_budhkar):
use the division rule of derivatives to get \[{(x^2-1)(1)-(x)(2x)}/(x^2-1)^2\]
OpenStudy (akshay_budhkar):
for the first one.. the answer is -(x^2+1)/(x^2-1)^2
OpenStudy (akshay_budhkar):
do you get it? or do u want me to explain more?
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OpenStudy (akshay_budhkar):
shessa???? do you know the formula?
OpenStudy (anonymous):
\[v*du/dx- u*dv/dx/v^2\]
OpenStudy (anonymous):
pls explain further.
OpenStudy (akshay_budhkar):
right.. so i have applied the same formula to get the answer..:)
OpenStudy (akshay_budhkar):
then you solve the bracket to get your answer.. you want me to do it too?
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OpenStudy (anonymous):
yup pls.
OpenStudy (akshay_budhkar):
(v∗du/dx−u∗dv/dx)/v2 its this the whole under v^2..
OpenStudy (akshay_budhkar):
oh ok you get in the numerator x^2-1-2x^2...
OpenStudy (anonymous):
x^2-1(1)=X^2-1
then x(2x)=?
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OpenStudy (akshay_budhkar):
sorry shessha
had a network problem..
you there????
OpenStudy (anonymous):
yup i'm still here
OpenStudy (akshay_budhkar):
yes come on twiddla
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