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OpenStudy (anonymous):
Find a polynomial of degree 3 that has zeros 1,-1,4. Show work please
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OpenStudy (anonymous):
Didn't we do this already..?
OpenStudy (amistre64):
multiply 3 terms of x's
OpenStudy (anonymous):
if a is a zero of the polynomial, then (x - a) is a factor of the polynomial
OpenStudy (amistre64):
where a,b,c are zeroes we have:
(x-a)(x-b)(x-c) = 0
OpenStudy (anonymous):
yeah its is
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OpenStudy (anonymous):
what do i do after (x-1)(x+1)(x-4)
OpenStudy (anonymous):
makes sense in my head :)
OpenStudy (amistre64):
:)
OpenStudy (amistre64):
after you get the terms; multiply them all together
OpenStudy (amistre64):
x-1
x+1
-------
x^2 -x
+x -1
-----------
x^2 +0 -1
...................................
x^2 -1
x - 4
---------
x^3 -x
-4x^2+4
-------------
x^3 -4x^2-x+4
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OpenStudy (anonymous):
so the three factors are (x - 1), [x -(-1)] i.e. (x + 1) and (x - 4)
now multiply all three to get the polynomial.........
OpenStudy (amistre64):
these terms are simply numbers in some form or fashion; so multiply them together like numbers
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