Find a polynomial of degree 3 that has zeros 1,-1,4. Show work please
Didn't we do this already..?
multiply 3 terms of x's
if a is a zero of the polynomial, then (x - a) is a factor of the polynomial
where a,b,c are zeroes we have: (x-a)(x-b)(x-c) = 0
yeah its is
what do i do after (x-1)(x+1)(x-4)
makes sense in my head :)
:)
after you get the terms; multiply them all together
x-1 x+1 ------- x^2 -x +x -1 ----------- x^2 +0 -1 ................................... x^2 -1 x - 4 --------- x^3 -x -4x^2+4 ------------- x^3 -4x^2-x+4
so the three factors are (x - 1), [x -(-1)] i.e. (x + 1) and (x - 4) now multiply all three to get the polynomial.........
these terms are simply numbers in some form or fashion; so multiply them together like numbers
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