64m^3x-8n^3x=
(64 m^3 - 8 n^3) x
what does the question ask? are there words?
no
(4m-2n)(14m^2+8mn+4n^2)
thats what i put on my home work she gave me this answer and said wk it out 8x(2m-n)(4m^2+2mn+n^2)
you are supposed to factor maybe?
yes that's another form you can get by factoring...
so either way is right she counted it wrong
ok perhaps it says \[64m^3x-8n^3x\]
in that case you have a common factor of 8 and x to pull out to write \[8x(8m^3-n^3)\]
yeah..either way its right unless she was looking for specific factor form...if the directions says so.
then the stuff inside the parentheses is the differnece of two cubes, and you factor as \[8x(2m-n)((2m)^2+2mn+n^2)\]
and then write \[8x(2m-n)(4m^2+2mn+n^2)\]
i am using the fact that \[a^3-b^3=(a-b)(a^2+ab+b^2)\] with \[a=2m,b=n\]
and that is the "final answer' as they say
thanks i will try that way
yw
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