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OpenStudy (anonymous):
64m^3x-8n^3x=
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OpenStudy (anonymous):
(64 m^3 - 8 n^3) x
OpenStudy (anonymous):
what does the question ask? are there words?
OpenStudy (anonymous):
no
OpenStudy (sriram):
(4m-2n)(14m^2+8mn+4n^2)
OpenStudy (anonymous):
thats what i put on my home work she gave me this answer and said wk it out 8x(2m-n)(4m^2+2mn+n^2)
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OpenStudy (anonymous):
you are supposed to factor maybe?
OpenStudy (anonymous):
yes that's another form you can get by factoring...
OpenStudy (anonymous):
so either way is right she counted it wrong
OpenStudy (anonymous):
ok perhaps it says
\[64m^3x-8n^3x\]
OpenStudy (anonymous):
in that case you have a common factor of 8 and x to pull out to write
\[8x(8m^3-n^3)\]
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OpenStudy (anonymous):
yeah..either way its right unless she was looking for specific factor form...if the directions says so.
OpenStudy (anonymous):
then the stuff inside the parentheses is the differnece of two cubes, and you factor as
\[8x(2m-n)((2m)^2+2mn+n^2)\]
OpenStudy (anonymous):
and then write
\[8x(2m-n)(4m^2+2mn+n^2)\]
OpenStudy (anonymous):
i am using the fact that
\[a^3-b^3=(a-b)(a^2+ab+b^2)\] with
\[a=2m,b=n\]
OpenStudy (anonymous):
and that is the "final answer' as they say
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OpenStudy (anonymous):
thanks
i will try that way
OpenStudy (anonymous):
yw
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