Ask your own question, for FREE!
Mathematics 7 Online
OpenStudy (anonymous):

64m^3x-8n^3x=

OpenStudy (anonymous):

(64 m^3 - 8 n^3) x

OpenStudy (anonymous):

what does the question ask? are there words?

OpenStudy (anonymous):

no

OpenStudy (sriram):

(4m-2n)(14m^2+8mn+4n^2)

OpenStudy (anonymous):

thats what i put on my home work she gave me this answer and said wk it out 8x(2m-n)(4m^2+2mn+n^2)

OpenStudy (anonymous):

you are supposed to factor maybe?

OpenStudy (anonymous):

yes that's another form you can get by factoring...

OpenStudy (anonymous):

so either way is right she counted it wrong

OpenStudy (anonymous):

ok perhaps it says \[64m^3x-8n^3x\]

OpenStudy (anonymous):

in that case you have a common factor of 8 and x to pull out to write \[8x(8m^3-n^3)\]

OpenStudy (anonymous):

yeah..either way its right unless she was looking for specific factor form...if the directions says so.

OpenStudy (anonymous):

then the stuff inside the parentheses is the differnece of two cubes, and you factor as \[8x(2m-n)((2m)^2+2mn+n^2)\]

OpenStudy (anonymous):

and then write \[8x(2m-n)(4m^2+2mn+n^2)\]

OpenStudy (anonymous):

i am using the fact that \[a^3-b^3=(a-b)(a^2+ab+b^2)\] with \[a=2m,b=n\]

OpenStudy (anonymous):

and that is the "final answer' as they say

OpenStudy (anonymous):

thanks i will try that way

OpenStudy (anonymous):

yw

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!