In which direction does the right side of this graph point? f(x)=-x^4-x^3+4x-2
the ^4 is even so the normal points up in both directions; like the ends of a parabola the "-" in front tells us to flip it; so that makes it point down and to the right
down if you consider it "pointing' anywhere
who writes this stuff?
somewhere in the East to South direction ;)
apex precalc.. ugh worst class
*class
*class
every time i write c l a s s it switches to clretrice
so how do i solve this problem
She doesn't mean class, she means CLASS
of course I know why they did that. The last three letters in CLASS spells something un-CLASSY
oh ahah yeah i guess, any idea how to solve this problem?
Um, it points downWARD
haha is that a guess or do you actually ahve some idea how to do this problem? bc im supper lost
haha is that a guess or do you actually ahve some idea how to do this problem? bc im supper lost
Well, as amistre said, they're referring to the end points of the parabola. You don't have to guess. Just graph it for yourself and you will see...
Well, it's not a parabola, but the end points of the graph point downward.... http://www.wolframalpha.com/input/?i=-x^4-x^3%2B4x-2
even exponents resemble "U" odd exponents resemble: " / "
the negative sign in front just turns them over
yeah, but it's negative even.....I understand what you're trying to do amistre...but she's already confused enough....just refer to it as negative even
even exponent, negative coefficient
so im just gunna say downward?
Well, you'll probably also have to explain why....
nope haha one word answer is all i have to put
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