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Mathematics 10 Online
OpenStudy (anonymous):

how do you simplify this: \[x ^{-1}+y ^{-1} \over (x+y)^{-1}\]

OpenStudy (anonymous):

((1/x)+(1/y))/(1/(x+y)), right? ((y/xy)+(x/xy))*(x+y) ((x+y)/xy)*(x+y) (x+y)^2/xy 1/y+2+1/x

OpenStudy (anonymous):

where did you get the *(x+y)??

OpenStudy (anonymous):

dividing by a fraction is the same as multiplying its inverse. Put mathematically, \[(1/x)^-1=x\]

OpenStudy (anonymous):

ok!! would you know how to simplify this one also? http://openstudy.com/groups/mathematics#/groups/mathematics/updates/4e3b74ee0b8b269281820dd8

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