Multiply (x – 4)(x^2 + 6x – 5)

x^3 + 2x^2 – 29^x + 20

x^3 – 5x^2 – 14^x + 20

x^3 + 6x2 – 13^x + 20

x^3 + 10x^2 – 19x + 20

Question

Multiply (x – 4)(x^2 + 6x – 5)

x^3 + 2x^2 – 29^x + 20

x^3 – 5x^2 – 14^x + 20

x^3 + 6x2 – 13^x + 20

x^3 + 10x^2 – 19x + 20

anonymous · Answer

Multiply everything in the first parenthesis by everything in the second parenthesis. Then group terms with the same exponent for x.

angela210793 · Answer

= x^3 + 2x^2 – 29^x + 20

anonymous · Answer

So x is the first thing in the first parenthesis, so multiplying it gives x^3+6x^2-5x

anonymous · Answer

-4 is the second thing. Multiplying it gives -4x^2 -24x - 20

anonymous · Answer

Adding those together gives x^3+2x^2-29x+20

(I made a mistake on the second step. It's +20 not -20)

anonymous · Answer

$$(x-4)(x^2+6x-5)$$Distribute x across the polynomial, and add to the distribution of -4 across the polynomial.
$$(x^3+6x^2-5x)+(-4x^2-24x+20)$$Simply:$$x^3+2x^2-29x+20$$