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OpenStudy (anonymous):
Simplify: (cos^2x-1)/cosx+1
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OpenStudy (lalaly):
cos^2x-1= (cosx+1)(cosx-1)
so jus cancel out cosx+1
the answer is cosx-1
OpenStudy (anonymous):
top is difference of 2 squares
a^2-b^2 = (a+b(a-b)
OpenStudy (anonymous):
man - you guys rock. thank you! never done trig IDs before and all these different formulas are messing me up - I'm forgetting the basics!
OpenStudy (anonymous):
yw - keep practicing - thats so important in maths
OpenStudy (anonymous):
sorry jim - there are no paren. on the numerator, i just did that to show the whole thing was the numerator.....does that change the answer?
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OpenStudy (anonymous):
\[\frac{\cos ^2x -1}{\cos x}+1\]
OpenStudy (anonymous):
?
OpenStudy (anonymous):
no the cosx+1 is the denom.
OpenStudy (anonymous):
(sorry i'm not familiar with the equation editor yet)
OpenStudy (anonymous):
then they did that problem above, layla and Jim
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OpenStudy (anonymous):
so cos^2x-1 even without the paren is still the diff. of two squares?
OpenStudy (anonymous):
parenthesis just for organization
OpenStudy (anonymous):
bc cos^2x-1 looks like cosxcosx-1 ... or?
OpenStudy (anonymous):
maybe i should just repost....lol
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