Question

Can someone please help me with this problem
-7+4i divided by 3-2i

Answer 1

(-29-2i)/13

Answer 2

\[\frac{-7+4i}{3-2i}=\frac{(-7+4i)(3+2i)}{(3-2i)(3+2i)}=\frac{-29-2i}{13}\]

Answer 3

can I ask how you got the -29 and the 13

Answer 4

\[(3-2i)(3+2i)=(3)^2-(2i)^2=9-4i^2=9-4(-1)=9+4=13\]

Answer 5

\[(-7+4i)(3+2i)=-21-14i+12i+8i^2=-21-2i-8=-29-2i\]

Answer 6

hope u got it.. :)

Answer 7

Yes that is a great job. I get it now. Thank you very much.