How do you solve
3x² - 12x + 12 = 0
??

Question

How do you solve 
3x² - 12x + 12 = 0
??

anonymous · Answer

Xsquared - 2x -2x +4 
x (x-2) -2(x-2)=0 (x-2)(x-2)=0 
x=2

anonymous · Answer

Yes, when you factor it you should get: 3(x^2 - 4x + 4)=0. Using FOIL method, we can re-write the equation to 3(x-2)(x-2)=0 thus the solution would be x=2 as a double root

anonymous · Answer

factor out the 3

3*(x^2-4x+4)=0

3*(x-2)^2

dumbcow · Answer

deja vu ... i know i've just seen this exact problem a little while ago

anonymous · Answer

lol @dumbcow me i asked the same question

dumbcow · Answer

haha nice

dumbcow · Answer

and now you are answering it...thats awesome, that means you get it now

anonymous · Answer

You should not need to use the quadratic formula.
3x² - 12x + 12 = 0  [multiply 3 from x^2 by +12] = 36
[Find factors of 36 that sum to 12] -6 x -6 = 12  and [-6] + [-6] = -12
Substitute into -12x
3x² - 6x - 6x + 12 = 0  [factorise in parts]
(3x² - 6x) - (6x + 12) = 0  
3x(x - 2) - 6(x - 2) = 0 

Answer 3(x - 2)(x - 2)  Hence x = 2