Question

sqrt2x^7sqrt6x

Answer 1

??

Answer 2

make sure to add parentheses around anything that is in a root please. ;)

Answer 3

o ok

Answer 4

It's good that you are doing a bunch of these. You really need to learn the rules of powers and roots and everything is much easier.

Answer 5

like....(2x)^7 is totally different than 2x^7

Answer 6

\[\sqrt{2x^7* \sqrt{6x}}\]

Answer 7

I am a bit lost one what the Prob is?

Answer 8

sorry...yes once I have it all under my belt, I'll be fine but I just can't seem to grasp the concepts right

Answer 9

you'll get it if you stick with it... that s for sure.

Answer 10

\[\sqrt{2x^7}* \sqrt{6x}\]

Answer 11

I'm hanging in there...just gets so frustrating! :(

Answer 12

I know what your talking about lol

Answer 13

u all are answering these like experts! wish I could get it back like that

Answer 14

Ok... cool... in that case you can bring the roots together for multiplication.. so ....

2*6*x*x^7 can all go under one radical...

Answer 15

ok

Answer 16

\[\sqrt{12x ^{8}}\]

Answer 17

yea, like nancy typed...

Answer 18

can this be simplified to 2x^4sqrt3?

Answer 19

\[2x ^{4}\sqrt{3}\]

Answer 20

there it is

Answer 21

YAAYYY!!! :)

Answer 22

do you see how you can take "pairs" out in a sense?

Answer 23

yes I can but I'm afraid, it gets much more difficult than this :(

Answer 24

like.... root(2*2*2)... you can take a pair out as one... so it's 2root(2)

Answer 25

yes i got that downpacked, I think lol

Answer 26

ok and that would be the sqrt 8 right?

Answer 27

or cube rt?

Answer 28

\[\sqrt[3]{270x}-\sqrt[3]{10x^4}\]