Question

can any1 help me please

Answer 1

?

Answer 2

\[2x^2 + 7x + 3\] this is the question we have to factorize it

Answer 3

(2x+1)(x+3)

Answer 4

ok

Answer 5

thanks lalay for the answer

Answer 6

the steps i take are:

take out any common factors; none in this case

look at the signs; the last number is +3, the + says we find 2 numbers to add that are factors of the first(2) times the last(3) number

the middle number is a +7, this tells the largest factor is positive ... in this case both factors are positive since we are adding, but its still goo to know.

this gives me a setup of: (x+B) (x+S), but since I use the first number to begin with I have to divid it out in the end which changes this set up to:

(x+B/2) (x+S/2)

now lets find some numbers :)

2(3) = 6 , factors of 6 that add to 7 are:

1,6 ; 1+6=7 <-- lets use 1 and 6 to fill in our setup
2,3 ; 2+3=5
...................................

(x+6/2) (x+1/2) ; now we simplify as much as possible

(x+3) (x+1/2) ; and if theres still a fraction, put the bottom in front; keep in mind that if we are looking for the "zeroes" of the function this step is good to stop on; it gives us what we need, but to factor lets continue...

(x+3) (2x+1) ; and there we go :)

Answer 7

thanks very much amistre