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can someone help me factor 4x^2+20x-24?
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=4(x^2+5x-6)
4(x+3)(x+2)
step1; factor out the commons stepB; factor more stepZeta; present finished form :)
the work involved can be minimal or maximal depending on the route you want to take
but the answer doesnt really care how you get it :)
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raheen, i assume, typoed his reply since this is NOT the answer: 4(x+3)(x+2)
\[x=-20+-\sqrt{(20)^2-4*4*(-24)}/2*4\] =[-20+-\sqrt{400+378}\]/8 \[\left[ -20+28\right]\]/8 \[8/8\] 1 ans using sri dhar acharya formula
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