Question

if limit as x approaches 3 is (3x-2)=7, find delta such that (3x-2)-7<.003 whenever 0 14 years ago

Answer 1

oh, not epsilon delta problem

Answer 2

yeah i dont understand it :/

Answer 3

hold on , let me find my Calc text

Answer 4

thanks

Answer 5

3x-2-7=3x-9=3(x-3)

Answer 6

yeh i got that far...but then my book goes into all this stuff i dont understand talking about why the answer (for their example) works

Answer 7

3(x-3)<.003
x-3<.001

Answer 8

thats the answer?? i hope so cuz thats what i got....

Answer 9

Delta=.001

Answer 10

thank you guys so much

Answer 11

thank you!

Answer 12

you are just using the definition of a limit just plug in the stuff into the definition and woolah

Answer 13

Basically you know
\[|f (x)\to L|<\epsilon \]

you wnat
\[0<|x-c|<\delta \]

so just play with algebra

Answer 14

the arrow suppose to be -?

Answer 15

minus

Answer 16

the arrow suppose to be -?

Answer 17

:)

Answer 18

the arrow suppose to be -?

Answer 19

\[\lim_{x \rightarrow c}f(x)=L\]

Answer 20

the arrow suppose to be -?

Answer 21

what imran is the formal definition for what i just typed

Answer 22

thanks guys woooo i think i get it now :)

Answer 23

the arrow suppose to be -?

Answer 24

has*

Answer 25

Trust me everyone hate these while learning them

Answer 26

you could say that again....my calc teacher gave us these summer assignments and learning them by myself is the hardest thing

Answer 27

summer assignment sucks