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solve by factoring: 6-7u=3u² Please explain how you did this! Thanks!
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3u^2+7u-6=0
take constant term and 1st term
well I've already gotten that first part
and find possible numbers that will go
Factor: 3u^2+7u-6=0 You need multiple of three and multiples of neg 6 which simultaneously multiply and add to give positive seven. (u+3)(3u-2)
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isn't -3u²+6-7u=0
aorry thats wrong
well I've already gotten that first part
Which one mine? Yours?
mine and yours this number cant be factored and urs the middle term is not right
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well I've already gotten that first part
this isn't for pleasure, this a math problem for school! I don't really think they would give me something impossible to solve!
nvm sorry chaise is right sorry im fasting
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