Question

What are the x– and y–intercepts of the graph of y = 2x^2 + 4x – 6?

x–intercepts: (1, 0) and (–3, 0)
y–intercept: (0, –3)

x–intercepts: (1, 0) and (–3, 0)
y–intercept: (0, –6)

x–intercepts: (–1, 0) and (3, 0)
y–intercept: (0, –3)

x–intercepts: (–1, 0) and (3, 0)
y–intercept: (0, –6)

Answer 1

x–intercepts: (1, 0) and (–3, 0)
y–intercept: (0, –6)

Answer 2

the x-intercepts is where y= 0
plug y = 0 to the equation
y = 2x^2 + 4x – 6
0 = 2x^2 + 4x – 6
divide all by 3 -> 0 = x^2 + 2x - 3
0 = (x+3)(x-1)
x = -3 or x = 1

Answer 3

the y-intercepts is where x =0
plug x = 0 to the equation
y = 2x^2 + 4x – 6
y = -6

Answer 4

therefore the answer is
x-intercepts : (1,0) and (-3,0)
y intercept : (0,-6)