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3a/12-1/4=5a/12+1/2
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maybe need some parentheses here to make it clear? or is it \[\frac{3a}{12}-\frac{1}{4}=\frac{5z}{12}+\frac{1}{2}\]?
(3a+3)/12=(5a+6)/12 3a+3=5a+6 -2a=3 a=-3/2
it is 3a12−14=5z12+12
if so, multiply both sides by 12 carefully to get \[3a-3=5a+6\]
then \[-3-6=5a-3a\] \[-9=2a\] \[a=-\frac{9}{2}\]
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