Ask your own question, for FREE!
Mathematics 18 Online
OpenStudy (anonymous):

Evaluate the exact value: tan(pi/6)

OpenStudy (anonymous):

sqrt{3}/3

OpenStudy (anonymous):

Steps?

OpenStudy (anonymous):

1/6(180) = 30 tan = sin/cos sin = 1/2 cos = sqrt{3}/2 (1/2)/(sqrt{3}/2) = sqrt{3}/3

OpenStudy (anonymous):

OpenStudy (anonymous):

find \[\frac{\pi}{6}\] on the unit circle on the last page of the cheat sheet. second coordinate is sine first coordinate is cosine. take \[\frac{\sin(\frac{\pi}{6})}{\cos(\frac{\pi}{6})}\]

OpenStudy (anonymous):

Oh my goodness satellite! Thank you that's an amazing tool

OpenStudy (anonymous):

i wish i had made it myself! i was starting to and then i found this as thought "why bother" just copy it. if you loose it google "paul's notes" and you will find some good cheat sheets and notes as well

OpenStudy (anonymous):

*lose

jimthompson5910 (jim_thompson5910):

\[\large \tan\left(\frac{\pi}{6}\right)\] \[\large \frac{\sin\left(\frac{\pi}{6}\right)}{\cos\left(\frac{\pi}{6}\right)}\] \[\large \frac{\frac{1}{2}}{\frac{\sqrt{3}}{2}}\] \[\large \frac{1}{2}\times\frac{2}{\sqrt{3}}\] \[\large \frac{1}{\sqrt{3}}\] \[\large \frac{\sqrt{3}}{3}\] So \[\large \tan\left(\frac{\pi}{6}\right)=\frac{\sqrt{3}}{3}\]

OpenStudy (anonymous):

Wonderful, thank you very much. Both of you!

Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!
Latest Questions
Breathless: Spooky witch but cute
3 hours ago 3 Replies 0 Medals
Arriyanalol: help
3 hours ago 10 Replies 2 Medals
Arriyanalol: @tinydinoUwU stop trying to find a argument u blad lil boy
1 day ago 5 Replies 3 Medals
Jaded012023: Please tell me what you all think of this song
6 hours ago 6 Replies 1 Medal
Arriyanalol: bro how
6 hours ago 2 Replies 3 Medals
Arriyanalol: cant wait for the new bluey movie in 2027
1 day ago 12 Replies 2 Medals
Can't find your answer? Make a FREE account and ask your own questions, OR help others and earn volunteer hours!

Join our real-time social learning platform and learn together with your friends!