In the diagram be… - QuestionCove
OpenStudy (anonymous):

In the diagram below of right triangle ACB, altitude CD is drawn to hypotenuse A If AB = 36 and AC = 12, what is the length of AD?

6 years ago
OpenStudy (anonymous):

B D C A $\text{BC}=36\text{ Sin}[\text{ArcCos}[12/36]]=24 \sqrt{2}$$\text{area} = \frac{1}{2}\text{BC } 12 =\text{ }\frac{1}{2}24 \sqrt{2}\text{ } 12 =144 \sqrt{2}$$\text{area} = \frac{1}{2}\text{CD } \text{AB}$$144 \sqrt{2} = \frac{1}{2}\text{CD } 36$$\text{CD}=8 \sqrt{2}= 11.3137$

6 years ago
OpenStudy (anonymous):