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simplify : (√125y^6)^(1/3)
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where does the root ends?
oh sorry. It ends at 6. the square root is cube rooted.
\[\sqrt[3]{125y^6} \]
like that?
yes exactly
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NONONON
5y
Its the cube root of the square root of 125y6
yes.
the answer is that^
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I think he means \[\sqrt[3]{\sqrt{125y^6}?}\]
the answer says y√5 but i want to know how to do it..
YESSS thats what i mean^^
well the y is simple y\[y^3*y^3 \] you can pull one out and then pull a y out
oh i see!
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this?
\[\Large \sqrt[3]{125y^6}\]
theres a square inside the cube root
\[\huge \sqrt[3]{\sqrt{125y^5}}\]
yes but y^6
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alright.
thanks
\[\Large \sqrt{5}y\]
tht's the answer.
howd you do it?
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the square root can be written as exponent 1/2 the cube root can be written as exponent 1/2
cube root is 1/3
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