Question

really bad at trig so im sure i messed up somewhere

Answer 1

whats the problem?

Answer 2

tan^2(x) = sec^2(x) -1 but you forgot to integrate

Answer 3

ya.. im not that good with integrating trig

Answer 4

or finding antiderivitive i should say

Answer 5

yeah it's a toughie, but once you take calculus 2 you'll get more used to it.

so your integral should be be evaluating tan(x) - x

Answer 6

got 1-(pi/4)

Answer 7

thanks for the help!

Answer 8

when you integrate a trig function, you have to think "is there a way to find something in which i can integrate". A lot of the time you can just use cos^2x +sin^2x = 1. In calculus 2 you'll find other ways such as double angles and stuff. But as for your answer, it is correct. I checked it on my calculator