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What is the domain of f(x)= 7- (x-3)^1/2?
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x-3>=0 domain is [3,+infinty[
are you working in a complex system?
I don't know it just say to tell the domain if f(x) is to be a real number
if f(x) to be real, the square root of (x-3) must be >=0, so your domain is x>=3
Since you have 7 - sqrt(x-3), then you have a domain of all real numbers, because 7 - sqrt(0) is 7. This is assuming that you have learned that sqrt(0) = 0. Provided you are not working with complex number (a.k.a. i = sqrt(-1)). Hope this helps. http://www.tutorsean.net
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