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Bob has $2.90 in pennies, nickels and dimes. He has the same number of pennies and nickels. If the number of dimes is 5 more than the number of nickels, how many of each type of oin does he have?
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x+x+x+5=2.90 3x=2.1 x=7 7 pennies 7 nickel and 10 dimes
oh cool, thanks
np
wait i think its wrong
10D +5N +P = 290 P=N D = 5+N use substitution 10(5+N) +5N +N = 290 50 +10N +5N +N = 290 16N+50 = 290 16N = 240 N = 15 then P = 15 D = 5+15 = 20
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