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Mathematics 7 Online
OpenStudy (anonymous):

3x^4y^2 / xy^2

OpenStudy (anonymous):

3x^3

OpenStudy (anonymous):

3x^3

OpenStudy (anonymous):

i'd look it as \[(3x^4y^2)*(x^-1y^-2)\]

OpenStudy (anonymous):

then al you have to do is add

OpenStudy (anonymous):

1/x is the same as x^-1

OpenStudy (anonymous):

yes - good thinking

OpenStudy (anonymous):

I do it that way, i can't stand division... ever since i hit the quotient rule in calc 1

OpenStudy (anonymous):

lol - quotient rule is irritating

OpenStudy (anonymous):

how do u guys get this answer, im only 14 btw

myininaya (myininaya):

you don't need quotient rule

myininaya (myininaya):

\[f(x)=\frac{h(x)}{g(x)} =>f(x)=h(x) \cdot [g(x)]^{-1}, g(x) \neq 0\]

myininaya (myininaya):

use product rule instead :)

myininaya (myininaya):

+chain rule

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