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log_{2}(x-10)-3=log_{2}(1-x)
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\[\log_2(x-10)-3=\log_2(1-x)\] \[\log_2(x-10)-\log_2(1-x)=3\] \[\log_2\left(\frac{x-10}{1-x}\right)=3\]
\[\frac{x-10}{1-x}=2^3\] continue to solve for x ...
you should get x=2
I should state here that this is only true if you are allow to work in the complex plane. clearly is you put in x=2 into the above equation you get negative values inside the log. if you are just working in R then you really have no solution. if you are allowed to work in C the 2 is the solution
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