Question

Solve the equation by factoring. 3z^2 + 3z - 6 =0

Answer 1

Pull out the three, you get 3(z-1)(z+2)=0

Answer 2

Then divide everything by 3.

Answer 3

\[ax^2+bx+c\]
to factor this we find two factors of a*c that have product a*c and have sum b
a=3, b=3,c=-6
a*c=3(-6)=-3(6)
b=6-3

so we have
\[3x^2+6x-3x-6=0\]
\[3x(x+2)-3(x+2)=0\]
\[(x+2)(3x-3)=0\]
\[3(x+2)(x-1)=0\]

Answer 4

so Z=1 or z=-2

Answer 5

why have i see this an similar problem and no one divide by 3 first?

Answer 6

\[3 \neq 0, x+2=0, x-1=0=>x=-2 or x=1\]

Answer 7

where x=z lol

Answer 8

\[z^2+z-2=0\] is a good first step

Answer 9

why factor out 3? just get rid of it, after all 0/3 is still 0