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Mathematics 17 Online
OpenStudy (anonymous):

solve for y' showing each step 3y^2y' + 2yy' = 5y' + 2x

OpenStudy (anonymous):

oh, here I thought it was differential equation problem

OpenStudy (anonymous):

similar to solving \[az+bz=5z+c\] for z

OpenStudy (anonymous):

1) subtract 5y' from both sides 2) factor out the y' from the left 3) divide 2x by whatever that factor is

OpenStudy (anonymous):

yeah i thought so too!

OpenStudy (anonymous):

@mac you get this?

OpenStudy (anonymous):

yeah, thanks!

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