use sqrt property to solve:
(5k-1)^2+126=1
k=??

Question

anonymous · Answer

not possible squares can't be equal to negative

anonymous · Answer

I am not sure

anonymous · Answer

$$(5k-1)^2=-125$$
$$5k+1=\pm\sqrt{125}=\pm5\sqrt{5}i$$
$$5k=-1\pm5\sqrt{5}i$$
$$k=-\frac{1}{5}\pm\sqrt{5}i$$

anonymous · Answer

ah I see complex lol sorry

anonymous · Answer

i think i saw SSG post complex questions before which is how i guessed.

anonymous · Answer

dang, wrong answer, unless I typed wrong, checking...

anonymous · Answer

the 1/5 is negative in both answers?

anonymous · Answer

yup

anonymous · Answer

hmmmm, then it seems incorrect

anonymous · Answer

nope the solution is perfect it can't be wrong

anonymous · Answer

okay, it must b my error somehow :(

anonymous · Answer

no it is postive

anonymous · Answer

i screwed up on one line and changed 
$$5k-1$$ to 
$$5k+1$$ by mistake. sorry

anonymous · Answer

great, no prob :)

anonymous · Answer

it is 
$$\frac{1}{5}-\sqrt{5}i$$ and 
$$\frac{1}{5}+\sqrt{5}i$$

anonymous · Answer

uh oh, still not it. One more guess for me left, any idea?

anonymous · Answer

lol you taking online test

anonymous · Answer

not a test, just some online homework:)

anonymous · Answer

I'm an english student, so I can help in that area but this algebra is beyond me!!

anonymous · Answer

you could try one fraction maybe

anonymous · Answer

oh okay let me see this time I will try to keep my eyes open properly open

anonymous · Answer

$$\frac{1\pm5\sqrt{5}i}{5}$$

anonymous · Answer

it is right for sure

anonymous · Answer

it's expecting two anwers, one positive one negative. I'll retype it and see

anonymous · Answer

maybe some problem with syntax. make sure the "i" is outside of the square root

anonymous · Answer

oh crap!! that's it!!

anonymous · Answer

dang, it was right with that second form you showed me. wow, thanks for all your work!!

anonymous · Answer

whew. hope you got it right
yw

anonymous · Answer

nope,lol... my bad

anonymous · Answer

:(