Question

m^4 * 2n^-3
is it 3m

Answer 1

U can't simplify that any more...

Answer 2

Where do u get 3m?

Answer 3

\[\large m^4*2n^{-3}=\frac{2m^4}{n^3}\]

Answer 4

D: ugh i hate math with a burning passion

Answer 5

U don't love math, u just get used to it..:-)

Answer 6

did i really put 2n? fml i meant 2m^-3

Answer 7

I thought that....

Answer 8

Didn't know which, though...

Answer 9

so sorry. `~`

Answer 10

Now it's like the other one, so 2 and add the exponents...

Answer 11

so was i right? 3m?

Answer 12

Add the exponents to get 4+(-3) = 1

So the final exponent is 1, which means that the answer is 2m^1 or just 2m

Answer 13

wouldn't you have to add m + 2m? :l

Answer 14

Look, m*m*m = m^3

Answer 15

So the m is already in the exponent.

Answer 16

No need to put again.

Answer 17

For example, x^2 times x^3 is x^5 (since 2+3=5)

or x^2 = x*x and x^3 = x*x*x

so (x^2)*(x^3) = (x*x)*(x*x*x) = x*x*x*x*x = x^5

Answer 18

Only the 2 lives by itself.

Answer 19

so the final answer is 2m?

Answer 20

yes, the final answer is 2m

Answer 21

I give u one

3^3* 5n^-2* 4n^4 = ?

Answer 22

See if u can figure out...

Answer 23

would it be 3^3 * 20n^2 or 60n?

Answer 24

This 3^3 * 20n^2 is right.....

Answer 25

Remember 3^3 = 3*3*3

Answer 26

woot

Answer 27

Same like n^3... = n*n*n so does 3^3 = 3*3*3 (letter instead of number)

Answer 28

i understand

Answer 29

i'll be posting a new question here shortly :)

Answer 30

So 3^3 * 20n^2 = 27* 20n^2 = 540n^2

Answer 31

\[2x ^{3}y ^{-3} * 2x ^{-1}y ^{3}\]

Answer 32

I think u can do it...

Answer 33

= 4x^2

Answer 34

Correct.

Answer 35

YAY!

Answer 36

:-)

Answer 37

:D thanks so much for all your help!

Answer 38

ur welcome, anytime...