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OpenStudy (anonymous):

Find integral sign 10/(4+x^2) dx using the substitution x=2 tan theta. (Give your answer in terms of x.)

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OpenStudy (anonymous):

\[\int\limits 10/(4+x^2) dx = 10*\int\limits1/(4+x^2) dx\] Let \[x=2*\tan \theta\]and \[dx = 2*\sec^2\theta d\theta\] Then, \[10*\int\limits 1/(4+4*\tan^2 \theta)*2*\sec^2 \theta d\theta\] Factor out a 4 in the denominator:\[10*\int\limits 1/(4*(1+\tan^2\theta))*2*\sec^2\theta d\theta\] Use the trig identity \[1+\tan^2\theta=\sec^2\theta\]Then, \[10*\int\limits (2*\sec^2\theta)/(4*\sec^2\theta) d\theta\]and \[10*\int\limits 1/2 d\theta=5*\int d\theta=5\theta\] Now, solve x=2*tan(theta) for theta and get \[\theta=\tan^-1(x/2)\]Thus, the answer is \[5*\tan^-1(x/2) + c\]

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