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OpenStudy (anonymous):

Find the vertices of the hyperbola with equation: (x-1)^2 - (y+2)^2 = 1

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OpenStudy (anonymous):

does anyone know how to do this?

OpenStudy (amistre64):

the hyper has vertexes along the axis that is positive in the equation; for this one that means the x axis. given that there are no denominatiors showing, we can determine that the distance from the center to a vertex is gonna be sqrt(1) the center is clued in by the numbers that modify x and y; in this case -1 and +2. the center is the opposite of these numbers. center = -(-1,2) = (1,-2) since we want to move alone the x part; a distance of 1 each way we can determine the vertexes as: (1+1, 2) and (1-1, 2)

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