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Mathematics
OpenStudy (anonymous):

Is correct the next factorization...?

OpenStudy (anonymous):

\[x^{5}+2z ^{2}+x ^{3}\]

myininaya (myininaya):

\[x^2 x^3+2x^2+x^2x=x^2(x^3+2+x)\]

OpenStudy (anonymous):

OpenStudy (anonymous):

see the jpg, is correct

OpenStudy (anonymous):

im starting with this, is so exciting

myininaya (myininaya):

i honestly don't know what's going on in your pdf

myininaya (myininaya):

or jpg

myininaya (myininaya):

you wanted to factored: \[x^5+2x^2+x^3?\]

OpenStudy (anonymous):

yes, \[(x-1) (x ^{4}-x ^{3}+2x+x ^{2}-2+x ^{2}-x+1)\]

OpenStudy (anonymous):

i made that

myininaya (myininaya):

-1 | 1 0 1 2 0 0 | -1 1 -2 0 0 --------------------------------- 1 -1 2 0 0 | 0 so we can write it as \[x^5+2x^2+x^3=(x+1)(x^4-x^3+2x^2)\]

myininaya (myininaya):

you have two different things but i don't really understand what the question is

myininaya (myininaya):

maybe amistre can figure out what the question is go amistre!

OpenStudy (amistre64):

x^5 +2z^2 +x^3 is what you have written down in the first part ... is that a typo?

myininaya (myininaya):

oh that is a z z's look like x's to me lol

OpenStudy (amistre64):

its the font in the equation editor

myininaya (myininaya):

look at his jpg above

OpenStudy (amistre64):

but since z and x are one key apart, its easy to typo them

OpenStudy (anonymous):

the factorization of x5+2x2+x3 have many ways of resolution, right?

OpenStudy (amistre64):

the jpg makes no sense to me as is :)

myininaya (myininaya):

those expressions that he has equal aren't equal

OpenStudy (amistre64):

yes it does; the first part is to take out any commons

OpenStudy (amistre64):

put in order for clarity: x^5 +x^3 +2x^2 x^2(x^3 +x +2) is a good step

myininaya (myininaya):

\[x^5+2x^2+x^3=(x+1)(x^4-x^3+2x^2) \]

OpenStudy (anonymous):

what kind of trinomial properties you can apply?

OpenStudy (amistre64):

x^3 +x +2 ; factors even more, and maybe we can take out a 1 or a 2 according to rational roots law

myininaya (myininaya):

\[x^5+2x^2+x^3=(x+1)(x^4-x^3+2x^2)=x^2(x+1)(x^2-x+2)\]

OpenStudy (amistre64):

-1 works out good :) (-1)^3 +(-1) +2 = -1-1-2 = 0 so its a root x^2(x+1)(left overs)

myininaya (myininaya):

is that what you wanted?

OpenStudy (anonymous):

is there a way to distribute the powers of x

myininaya (myininaya):

?

OpenStudy (amistre64):

maybe, but your question isnt making any sense

OpenStudy (anonymous):

i dont like the x4 -x3

OpenStudy (amistre64):

according to myins way: x^5 +2x^2 +x^3 (x+1)(x^4 −x^3 +2x^2) x^2 (x+1) (x^2 −x +2)

OpenStudy (anonymous):

distribute the whole factorized equation to see the skeleton

myininaya (myininaya):

what is your definition of the skeleton?

OpenStudy (anonymous):

the heart of the apple

OpenStudy (amistre64):

if your using a translating website; you might wanna think about picking a new one :)

myininaya (myininaya):

apples don't have hearts

OpenStudy (anonymous):

the carrot, the true, the whole mechanism!

myininaya (myininaya):

i don't understand i'm sorry

OpenStudy (anonymous):

haha, forget it, you were right!

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