Is correct the next factorization...?
\[x^{5}+2z ^{2}+x ^{3}\]
\[x^2 x^3+2x^2+x^2x=x^2(x^3+2+x)\]
see the jpg, is correct
im starting with this, is so exciting
i honestly don't know what's going on in your pdf
or jpg
you wanted to factored: \[x^5+2x^2+x^3?\]
yes, \[(x-1) (x ^{4}-x ^{3}+2x+x ^{2}-2+x ^{2}-x+1)\]
i made that
-1 | 1 0 1 2 0 0 | -1 1 -2 0 0 --------------------------------- 1 -1 2 0 0 | 0 so we can write it as \[x^5+2x^2+x^3=(x+1)(x^4-x^3+2x^2)\]
you have two different things but i don't really understand what the question is
maybe amistre can figure out what the question is go amistre!
x^5 +2z^2 +x^3 is what you have written down in the first part ... is that a typo?
oh that is a z z's look like x's to me lol
its the font in the equation editor
look at his jpg above
but since z and x are one key apart, its easy to typo them
the factorization of x5+2x2+x3 have many ways of resolution, right?
the jpg makes no sense to me as is :)
those expressions that he has equal aren't equal
yes it does; the first part is to take out any commons
put in order for clarity: x^5 +x^3 +2x^2 x^2(x^3 +x +2) is a good step
\[x^5+2x^2+x^3=(x+1)(x^4-x^3+2x^2) \]
what kind of trinomial properties you can apply?
x^3 +x +2 ; factors even more, and maybe we can take out a 1 or a 2 according to rational roots law
\[x^5+2x^2+x^3=(x+1)(x^4-x^3+2x^2)=x^2(x+1)(x^2-x+2)\]
-1 works out good :) (-1)^3 +(-1) +2 = -1-1-2 = 0 so its a root x^2(x+1)(left overs)
is that what you wanted?
is there a way to distribute the powers of x
?
maybe, but your question isnt making any sense
i dont like the x4 -x3
according to myins way: x^5 +2x^2 +x^3 (x+1)(x^4 −x^3 +2x^2) x^2 (x+1) (x^2 −x +2)
distribute the whole factorized equation to see the skeleton
what is your definition of the skeleton?
the heart of the apple
if your using a translating website; you might wanna think about picking a new one :)
apples don't have hearts
the carrot, the true, the whole mechanism!
i don't understand i'm sorry
haha, forget it, you were right!
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