Mathematics
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OpenStudy (anonymous):
Is correct the next factorization...?
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OpenStudy (anonymous):
\[x^{5}+2z ^{2}+x ^{3}\]
myininaya (myininaya):
\[x^2 x^3+2x^2+x^2x=x^2(x^3+2+x)\]
OpenStudy (anonymous):
OpenStudy (anonymous):
see the jpg, is correct
OpenStudy (anonymous):
im starting with this, is so exciting
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myininaya (myininaya):
i honestly don't know what's going on in your pdf
myininaya (myininaya):
or jpg
myininaya (myininaya):
you wanted to factored:
\[x^5+2x^2+x^3?\]
OpenStudy (anonymous):
yes, \[(x-1) (x ^{4}-x ^{3}+2x+x ^{2}-2+x ^{2}-x+1)\]
OpenStudy (anonymous):
i made that
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myininaya (myininaya):
-1 | 1 0 1 2 0 0
| -1 1 -2 0 0
---------------------------------
1 -1 2 0 0 | 0
so we can write it as
\[x^5+2x^2+x^3=(x+1)(x^4-x^3+2x^2)\]
myininaya (myininaya):
you have two different things
but i don't really understand what the question is
myininaya (myininaya):
maybe amistre can figure out what the question is
go amistre!
OpenStudy (amistre64):
x^5 +2z^2 +x^3 is what you have written down in the first part ... is that a typo?
myininaya (myininaya):
oh that is a z
z's look like x's to me lol
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OpenStudy (amistre64):
its the font in the equation editor
myininaya (myininaya):
look at his jpg above
OpenStudy (amistre64):
but since z and x are one key apart, its easy to typo them
OpenStudy (anonymous):
the factorization of x5+2x2+x3 have many ways of resolution, right?
OpenStudy (amistre64):
the jpg makes no sense to me as is :)
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myininaya (myininaya):
those expressions that he has equal aren't equal
OpenStudy (amistre64):
yes it does; the first part is to take out any commons
OpenStudy (amistre64):
put in order for clarity:
x^5 +x^3 +2x^2
x^2(x^3 +x +2) is a good step
myininaya (myininaya):
\[x^5+2x^2+x^3=(x+1)(x^4-x^3+2x^2) \]
OpenStudy (anonymous):
what kind of trinomial properties you can apply?
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OpenStudy (amistre64):
x^3 +x +2 ; factors even more, and maybe we can take out a 1 or a 2 according to rational roots law
myininaya (myininaya):
\[x^5+2x^2+x^3=(x+1)(x^4-x^3+2x^2)=x^2(x+1)(x^2-x+2)\]
OpenStudy (amistre64):
-1 works out good :) (-1)^3 +(-1) +2 = -1-1-2 = 0 so its a root
x^2(x+1)(left overs)
myininaya (myininaya):
is that what you wanted?
OpenStudy (anonymous):
is there a way to distribute the powers of x
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myininaya (myininaya):
?
OpenStudy (amistre64):
maybe, but your question isnt making any sense
OpenStudy (anonymous):
i dont like the x4 -x3
OpenStudy (amistre64):
according to myins way:
x^5 +2x^2 +x^3
(x+1)(x^4 −x^3 +2x^2)
x^2 (x+1) (x^2 −x +2)
OpenStudy (anonymous):
distribute the whole factorized equation to see the skeleton
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myininaya (myininaya):
what is your definition of the skeleton?
OpenStudy (anonymous):
the heart of the apple
OpenStudy (amistre64):
if your using a translating website; you might wanna think about picking a new one :)
myininaya (myininaya):
apples don't have hearts
OpenStudy (anonymous):
the carrot, the true, the whole mechanism!
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myininaya (myininaya):
i don't understand i'm sorry
OpenStudy (anonymous):
haha, forget it, you were right!