Question

Joe has a collection of nickels and dimes that is worth $7.65. If the number of dimes was doubled and the number of nickels was increased by 35, the value of the coins would be $14.30. How many nickels and dimes does he have?
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Answer 1

I need help big time... there was someone helping me a few mins ago but idk where he went

Answer 2

I can help.

Answer 3

thank u

Answer 4

Let n = number of nickels
Let d = number of dimes
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The question gives you info to make two equations :

0.05*n + 0.10*d = 7.65
0.05*(n +35) + 0.10*(2d) = 14.30
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Start by simplifying and rewriting the second equation :

0.05*(n +35) + 0.10*(2d) = 14.30
0.05*n + (0.05*35) + 0.20*d = 14.30
0.05*n + 1.75 + 0.20*d = 14.30
0.05*n + 0.20*d = 12.55
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Now the two equations are :

0.05*n + 0.10*d = 7.65
0.05*n + 0.20*d = 12.55

Subtract the second equation from the first and solve for d :

- 0.10 * d = - 4.90

d = ( - 4.90 / - 0.10 ) = 49

Substitute that value of d into the first equation and solve for n :

0.05*n + 0.10*d = 7.65

0.05*n + (0.10 * 49) = 7.65

0.05*n + 4.90 = 7.65

0.05*n = ( 7.65 - 4.90 )

0.05*n = 2.75

n = ( 2.75 / 0.05 ) = 55
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You can check to verify that the values n = 55 and d = 49 satisfy both equations.

Answer 5

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Answer 6

thank you so so soooooo much....

Answer 7

Abe, i have solutions of all of these with me, coz i help manyyy college people.

You welcome 87