Question

v^2+64-16v= (v-8)(v+8)...right? I'm sorry for my neediness, I just have no one home to double check my work b4 submission! ;0

Answer 1

Just a bit mistake in signs

Answer 2

no, you're thinking of the difference of squares formula

Answer 3

(v-8)(v-8)

Answer 4

or \[v^2+64-16v=(v-8)^2\]

this is a perfect square

Answer 5

so use the perfect square formula \[a^2-2ab+b^2=(a-b)^2\]

Answer 6

agree.

Answer 7

in this case, a=v and b=8

Answer 8

eiyiyi...yes!!