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v^2+64-16v= (v-8)(v+8)...right? I'm sorry for my neediness, I just have no one home to double check my work b4 submission! ;0
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Just a bit mistake in signs
no, you're thinking of the difference of squares formula
(v-8)(v-8)
or \[v^2+64-16v=(v-8)^2\] this is a perfect square
so use the perfect square formula \[a^2-2ab+b^2=(a-b)^2\]
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agree.
in this case, a=v and b=8
eiyiyi...yes!!
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