Question

tell me if this is wrong=
8v²+31v-4
(8v²-1v)(32v-4)
1v(8v-1) 4(8v-1)
(v+4)(8v-1)

Answer 1

Its right. :)

Answer 2

\[8v2+31v−4\]
\[8v2+32v−1v−4\]
\[8v(v+4)−1(v+4)\]
\[(8v−1)((v+4)\]
ur answer and this answer is same and ur process is also right hence u r right

Answer 3

thank you! what could I do to simplify this:
(32v²-4v)(-8v+1)

Answer 4

see here :
\[(32v^2-4v)(-8v+1)\]
as we know \[( a+b)( c+d)=ac+bc+ad+bd\]
hence here
\[32v^2(-8v)-4v(-8v)+32v^2(1)-4v(1)\]
\[-256v^3+32v^2+32v^2-4v\]
\[-256v^3+64v^2-4v\]