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3(n+4) = 7
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I'm in over my head.
\[\large 3(n+4) = 7\] \[\large n+4 = \frac{7}{3}\] \[\large n = \frac{7}{3}-4\] \[\large n = -\frac{5}{3}\]
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see here \[3(n+4)=3n+3(4)\] \[3n+12=7\] \[3n=-5\] \[n=-5/3\]
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