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The number of digits in the sum 100+ 100^2 + 100^3 + ….+ 100^2011 is
d) None of these
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ah 100 + 100^2 = 100 + 10000 = 10100
100 + 10000 + 1000000 = 10100100
so 2 zero position and that makes 2X2011 =2022 and plus 1 position the answer is 4023
ah I meant option A not B read the options wrong
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