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OpenStudy (anonymous):
The number of digits in the sum 100+ 100^2 + 100^3 + ….+ 100^2011 is a) 4023 b) 4022 c) 4024 d) None of these
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OpenStudy (anonymous):
B
OpenStudy (anonymous):
How bhaiya?
OpenStudy (anonymous):
ah 100 + 100^2 = 100 + 10000 = 10100 100 + 10000 + 1000000 = 10100100
OpenStudy (anonymous):
so 2 zero position and that makes 2X2011 =2022 and plus 1 position the answer is 4023
OpenStudy (anonymous):
ah I meant option A not B read the options wrong
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